## What is maximum resistance?

We know that combining resistors in parallel reduces equivalent resistance, and combining resistors in series increases equivalent resistance. Combining all five resistors in series will give you the maximum resistance. Rmax=R1+R2+R3+R4+R5. Rmax=R+R+R+R+R=5R. Rmax=5×51=1O

**What is the maximum resistance which can be made using four resistors? **

2 Ohms

### What is the minimum resistance which can be made using 4 resistors each of 4 ohm?

Answer. Answer: 5 ohms is the minimum resistance that we can get.

**What can be the maximum resistance which can be made using 5 resistors of 2 ohm each? **

The answer is (d). 1 O Maximum resistance can be achieved when resistors connected in series.

## What is the minimum resistance which can be obtained using five resistors each of 1/2 O?

The minimum resistance that can be achieved using five resistors are 0. 04 ohms. Explanation: The equivalent resistance to a parallel combination of resistors is minimal.

**What is the maximum resistance which can be made using 5 resistors each of 1.5 ohm? **

Solution: The best resistance can be achieved in series combinations. Thus, Rs=5(15O)=1O.

### What is the maximum resistance which can be made using 5 resistors each of 1/5 ohm *?

Answer. Maximum resistance can be achieved using five resistors of 1/5 ohms each.

**When n resistors of equal resistance R are connected in series and in parallel respectively then the ratio of their effective resistance is? **

Therefore, the required ratio is n2 to 1.

## What is the total resistance of N resistors each of resistance R connected in a series B parallel?

Ohm’s Law and Parallel Resistances This means that the total resistance of a parallel circuit equals the sum of the inverses of each individual resistance. Therefore, for every circuit with n number or resistors connected in parallel, Rn(parallel)=1R1+1R2+1R3… +1Rn.

**What is the equivalent resistance of the network shown in the figure? **

5R/11.

### How do you find the resistance between A and B?

So we get the equivalent by the formula, 1Req=1R1+1R2+1R3+…. We now have two resistances in series in the top wire between points A and B. So the equivalent resistance between the points A and B will be 11R15.

**How do you calculate the resistance of a circle? **

The sum of all currents flowing through each path equals the total current from the source. The following formula can be used to calculate total resistance in a Parallel circuit: 1/Rt=1/1R2 + 1/1R3 +… t=R (t).

## What is the resistance across A and B in the following circuit as shown in Figure?

In fig(viii), the resistors between arm FC are in parallel, hence the equivalent resistance between A and B is 2+22×2=1O

**What is the resistance between P and Q of the following circuit each resistance is of 1 ohm? **

Each resistance has a value of 1O, and wires between eb & bd have a resistance of 0.5O. Experts will guide you through the steps to clear your doubts and score high marks in exams.

### What is the equivalent resistance between any two corners of the triangle?

The equivalent resistance between two corners is 1. 34 ohms.

**What is the equivalent resistance between any two vertices of a triangle? **

Therefore, the equivalent resistance across two vertices in an equilateral triangle of 4Ohm is achieved.

## How many different combinations may be obtained with three resistors each having the resistance R?

4 different combinations